Using hexdump to print binary protocols

I had to work on an image yesterday where I couldn't install anything and the amount of pre-installed tools was quite limited. And I needed to debug an input device, usually done with libinput record. So eventually I found that hexdump supports formatting of the input bytes but it took me a while to figure out the right combination. The various resources online only got me partway there. So here's an explanation which should get you to your results quickly.

By default, hexdump prints identical input lines as a single line with an asterisk ('*'). To avoid this, use the -v flag as in the examples below.

hexdump's format string is single-quote-enclosed string that contains the count, element size and double-quote-enclosed printf-like format string. So a simple example is this:

$ hexdump -v -e '1/2 "%d\n"' 
-11643
23698
0
0
-5013
6
0
0

This prints 1 element ('iteration') of 2 bytes as integer, followed by a linebreak. Or in other words: it takes two bytes, converts it to int and prints it. If you want to print the same input value in multiple formats, use multiple -e invocations.

$ hexdump -v -e '1/2 "%d "' -e '1/2 "%x\n"' 
-11568 d2d0
23698 5c92
0 0
0 0
6355 18d3
1 1
0 0

This prints the same 2-byte input value, once as decimal signed integer, once as lowercase hex. If we have multiple identical things to print, we can do this:

$ hexdump -v -e '2/2 "%6d "' -e '" hex:"' -e '4/1 " %x"' -e '"\n"'
-10922  23698 hex: 56 d5 92 5c
     0      0 hex: 0 0 0 0
 14879      1 hex: 1f 3a 1 0
     0      0 hex: 0 0 0 0
     0      0 hex: 0 0 0 0
     0      0 hex: 0 0 0 0

Which prints two elements, each size 2 as integers, then the same elements as four 1-byte hex values, followed by a linebreak. %6d is a standard printf instruction and documented in the manual.

Let's go and print our protocol. The struct representing the protocol is this one:

struct input_event {
#if (__BITS_PER_LONG != 32 || !defined(__USE_TIME_BITS64)) && !defined(__KERNEL__)
        struct timeval time;
#define input_event_sec time.tv_sec
#define input_event_usec time.tv_usec
#else
        __kernel_ulong_t __sec;
#if defined(__sparc__) && defined(__arch64__)
        unsigned int __usec;
#else
        __kernel_ulong_t __usec;
#endif
#define input_event_sec  __sec
#define input_event_usec __usec
#endif
        __u16 type;
        __u16 code;
        __s32 value;
};

So we have two longs for sec and usec, two shorts for type and code and one signed 32-bit int. Let's print it:

$ hexdump -v -e '"E: " 1/8 "%u." 1/8 "%06u" 2/2 " %04x" 1/4 "%5d\n"' /dev/input/event22 
E: 1553127085.097503 0002 0000    1
E: 1553127085.097503 0002 0001   -1
E: 1553127085.097503 0000 0000    0
E: 1553127085.097542 0002 0001   -2
E: 1553127085.097542 0000 0000    0
E: 1553127085.108741 0002 0001   -4
E: 1553127085.108741 0000 0000    0
E: 1553127085.118211 0002 0000    2
E: 1553127085.118211 0002 0001  -10
E: 1553127085.118211 0000 0000    0
E: 1553127085.128245 0002 0000    1

And voila, we have our structs printed in the same format evemu-record prints out. So with nothing but hexdump, I can generate output I can then parse with my existing scripts on another box.